← All simulations

Bearings & Distances

east=dsin(θ),  north=dcos(θ)\text{east} = d\sin(\theta),\; \text{north} = d\cos(\theta)
Distance O to B12.8 km
Bearing of B from O098.7°
Back bearing (O from B)278.7°
  • Get the direct distance from O to B to at least 15 km
  • Make B lie due east of O (resultant bearing of about 090°)
  • Sail 10 km due north (000°), then 10 km due east (090°) — find the direct distance back (10√2 ≈ 14.14 km)
  • Make the back bearing from B to O exactly 040° (so B lies on a bearing of 220° from O)
  • Align both legs in roughly the same direction to push the direct distance above 20 km