Food Chains & Energy Flow

E_{next} = E \times \frac{10}{100}

Producer energy10,000 kJ

Reaches the herbivore1,000 kJ

Reaches the top predator10 kJ

Share reaching the top0.10%

Producer energy10000 kJ

Energy transfer per level10 %

Set the producers to capture 10 000 kJ of energy
With energy flowing up, make 1000 kJ reach the herbivores
Show that 9000 kJ is lost between the producers and the herbivores
Follow the chain to the top — bring the snake down to about 10 kJ
Raise the transfer efficiency until 0.8% of the producers’ energy reaches the top