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Hooke's Law

F=kx⇒x=mgk=0.2 mF = kx \Rightarrow x = \frac{mg}{k} = 0.2\,\text{m}
Extension19.6 cm
Force9.8 N
Energy stored0.96 J
  • Produce an extension of about 10 cm
  • Keep the extension under 3 cm
  • Stretch the spring to about 20 cm
  • Reach a 15 cm extension using a spring constant of 120 N/m